What does stringtokenizer do regex package StringTokenizer st = new StringTokenizer(str, delim); where “str” is the string to be parsed and “delim” is the delimiter character or string. How do you know how many tokens are in a string? I've been trying to get my program to pull one word out at time from my . nextToken(); can be used in a loop to select all the entries in that string. hasMoreTokens just tells you if there are more words left before the end of the string. 10:. Using a StringTokenizer to count the tokens of a String implies that you should: Get a new StringTokenizer for a specified String, using the StringTokenizer(String str) constructor. The StringTokenizer class in Java, part of the java. The default StringTokenizer uses whitespace as a delimiter, but under a very unique definition of whitespace (e. You should set it to true. It is a simple and fast way to tokenize a string, splitting it into smaller parts The string tokenizer class allows an application to break a string into tokens. docx The string tokenizer class allows an application to break a string into tokens. The StringTokenizer StringTokenizer breaks your string into several pieces depending on what you give as the second argument. Return Value. hasMoreTokens()){ System. What is a StringTokenizer in Java? The string tokenizer class allows an application to break a string into tokens. Use of String. "; StringTokenizer st = new StringTokenizer(a); while (st. In polymorphic case which you created or already has more implementation of the Enumeraion interface you will use the hasMoreElements which is part of the Enumeraion interface. Reply reply [deleted] • The name "Scanner" is a bit misleading, because the word is often used to mean a lexical analyzer, and that's not what Scanner is for. ", although, I might also recommend using Scanner – MadProgrammer The nextToken() method of StringTokenizer class is used to return the next token one after another from this StringTokenizer. Using tokenizer to count number of words in a file? 1. public void getWord(){ ASCIIDataFile i The StringTokenizer is used to break a String into tokens. delimiter(). toCharArray(); Only real constraints I have with this assignment is not being able to use StringTokenizer and regex. It’s very similar with one of the When using a string tokenizer , how do I check the next character after a token if it is a delimiter? If you use the 3 argument constructor for StringTokenizer, then 3rd argument says whether or not the delimiters are returned as tokens. StreamTokenizer provides similar functionality but the tokenization method of StringTokenizer is much simpler than the one used by the StreamTokenizer class. StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. Try the split method of String. In this post, we will learn about StringTokenizer in Java. A StringTokenizer object internally maintains a current position within the string to be tokenized. The set of delimiters (the characters that separate tokens) may be No, your code won't work. I'm trying to devide a way to do the following: To help us explain how you would do it in Ruby, it would be great if you give us a snippet of code with StringTokenizer that does what you want to do with your files/strings. The code: StringTokenizer st The StringTokenizer class helps us splitStringsinto multiple tokens. But as @user3437460 said, StringTokenizer is now legacy; String. Commented Jul 6, 2015 at 7:44. The set of delimiters (the characters that separate tokens) may be Java StringTokenizer Constructors. It is a simple and fast way to tokenize a string, splitting it into smaller parts based on delimiters. Unlike StreamTokenizer, StringTokenizer does not differentiate among identifiers, numbers and It would seem that StringTokenizer is the most straight forward approach, but the Javadocs really say you should prefer to use the regex aproach. Use the simpler String. This is my code: System. The set of delimiters (the characters that separate tokens) may be The StringTokenizer class in Java is a legacy class that tokenizes (split) strings into individual tokens based on a specified delimiter. ask dan about the system. After the Java StringBuffer, you must be curious about StringTokenizer. I have a stringtokenizer object that is breaking apart a string(a mathematical expression). Technical questions should be asked in the appropriate category. Using the tokenizer String method of StringTokenizer class, we can split a string into its constituent parts. According to the Oracle, StringTokenizer in Java is a class that allows an application to break a string into tokens. com. 10) so that it does not include punctuation characters in its character count. pattern()). Its documentation states: StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. Let's start by eliminating StringTokenizer. Help; Remember Me? Forum; FAQ; Calendar; Forum Actions There is no StringTokenizer constructor or factory method that does what you want any more simply. It first explains what a StringTokenizer does along with the basic concepts of delimiters and tokens. Follow answered Oct 3, 2018 at 23:27. parseInt to do that). The set of delimiters (the characters that separate tokens) may be StringTokenizer t = new StringTokenizer(s,"=,;"); to this: StringTokenizer t=new StringTokenizer(s," =,;"); gives the output: helloiamthekingoftheworld 8. util package and allows an application to break the string into tokens by specifying a delimiter. Is it any faster? In order to find out if this is any faster, I wrote a program to compare speeds in the following four methods: Use of StringTokenizer. parseInt(token. However, if I assign those variable in my while loop, the iteration will overwrite my variables, and they will all return with the same value. countTokens() returning erroneous value in for loop condition. 5k 14 14 gold badges 73 73 silver badges 115 115 bronze badges. You wrote. If I were to use a couple of Arrays I could have done it a while ago but having to use the StringTokenizer is driving me nuts. NET Solution. Note that if delim is null, this constructor does not throw an exception Also, NOTE: Whoever gave you this assignment, ask them to read the documentation for StringTokenizer, where you'll find this excerpt StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. Hint: You must change the set of delimiters used by the StringTokenizer class. The third parameter is a boolean value that specifies whether delimiters are required as tokens. String Tokenizer in java. nextToken());} Token In a string that contains a series of words or other items of data separated by spaces or other characters, the programming term for the data items is Unfortunately, Scanner cannot do token counting without consuming these tokens from the input. new StringTokenizer(yourString, yourDelimiters, true); I made a calculator and now improving it so that it reads one line of code and turns it into three variables a: first number, b: second number, and function: what it does example: 10 * 10. length(); i++) { char c = myString. Betlista Betlista. regex package instead. Commented May 11, 2011 at 14:41. Constructs a string tokenizer for the specified string. A programmer is Pages 11. util package, is a legacy class used to break a string into tokens. Especially given this quote from the javadoc of nextToken():. Full documentation is also included in the zipped . It is a method of String class. answered Jun 13, 2013 Why do you use a StringTokenizer?Just iterate the String:. 알맞는 메소드를 사용한다. The Java StringTokenizer countTokens() method is used to calculate the number of times that this tokenizer's nextToken method can be called before it generates an exception. What does StringTokenizer do in Java? The string tokenizer class allows an application to break a string into tokens. CS 3230. Follow answered Feb 6, 2018 at 9:42. This class can split a String into many smaller strings. The `StringTokenizer` class provides a convenient way to tokenize strings, but it is essential to understand its limitations and consider alternatives for more complex scenarios. Syntax: public String nextToken() Parameters: The method does not take any parameters. The set of delimiters (the characters that separate tokens) may be StringTokenizer class in Java provides a tokenizer String method for splitting a string into tokens based on a specified delimiter. So in order to access those tokens, you have to save them in a list: Use split(), it supports regex, unlike StringTokenizer. The constructor StringTokenizer(String) is same as StringTokenizer(String, "\t\n\f\r") hence it works for your string. blanks, new lines, carriage returns, and You are using the StringTokenizer in the wrong way. e. The method call returns the number This does correctly answer the question of whether to use split or StringTokenizer. split() is recommended in new code. How to change Stringtokenizer to String. A larger loop can read the file in. for(int i = 0; i < myString. After creating the tokenizer, the reading position is on "0". Don't force String. 1. Download our vscode extension. When you first try to reference users[nm] its value is going to be null. Below programs illustrate the working of nextToken() Method In simple case which uses just the StringTokenizer you can use the hasMoreTokens method. JHeath41. split(sc. StringTokenizer The primary purpose of this class is provide methods to split string in java. println(st. Give examples of whitespace. It is recommended that anyone seeking this functionality use the split method of The string tokenizer class allows an application to break a string into tokens. CS. "); while (strToken. 4. So, what are you waiting for? If you want for string "cars:ford> chevy 123" to have 4 tokens, this is what you have to do So change it to. +1 but as mentioned in StringTokenizer documentation "StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. txt file for that string StringTokenizer deals only with splitting strings into words. BufferedReader; import java. hasMoreElements() needs to be there because StringTokenizer implements the Enumeration interface. Keep it simple. An instance of StringTokenizer behaves in one of two ways, depending on whether it A naive implementation of StringTokenizer should take O(n * d) where n is the length of string and d is the number of delimiters. Follow asked Jul 16, 2009 at 16:40. 1° Esempio – Lettura Stringa. 3/30/2022. What is the way to use stringtokenizer. swing. The StringTokenizer class helps us split Strings into multiple tokens. , every other definition in the Java APIs seems to include line tabulation, whereas the default StringTokenizer does not. A token is returned by taking a substring of the string that was used to create the StringTokenizer object. char[] chars = myString. i I'm trying to use the class StringTokenizer to split a character string from a text file, but when I'm running the app, the compiler prints in the Netbeans console the words that I'm splitting but also shows an exception. nextToken()); Given above codes, the output is following, the STRING TOKENIZER CLASS ALLOWS an APPLICATION to BREAK a STRING As others explained, the toString is not the place to be instantiating your class. By mastering its usage, you can enhance your string manipulation capabilities within Java applications. All it is is a substitute for the scanf() function you find in C, Perl, et al. Throws NoSuchElementException if there are no more tokens in this tokenizer's string. When you then call nextToken() after already having extracted all the tokens, why are you surprised that you get an exception?. The set of delimiters (the characters that separate StringTokenizer class in Java is used to break a string into tokens. Just take a look at the javadoc. . java. Declaration. Covering popular subjects like HTML, CSS, JavaScript, Python, SQL, Java, and many, many more. You could do something similar with a StringTokenizer if you liked, only you would need at least two if statements to check whether there were enough tokens. The StringTokenizer class has three constructors. util. It breaks the first string whenever any of the characters of the second StringTokenizer class in Java is used to break a string into tokens. However 1, this still leaves you with the awkward problem of dealing with whitespace. One must go through StringTokenizer class where concepts and constructors are discussed which help in Tutorial explains how to use java. hasMoreTokens()) {System. Share. StringTokenizer (String str, String delim, boolean returndelims): This creates a string tokenizer for a specified string, and tokens will be generated based on a specified delimiter. While you're iterating over the tokens you never increment k and l which remain 0 through out; implying that you're always checking for the first keyword and data type only. A string can be divided into tokens (Java tokens are the text (words) that are produced when the Java compiler splits a line of code. It is simple way to break a String. split() and regular expressions are often preferred for string manipulation tasks. java; stringtokenizer; Share. A Simple Example of StringTokenizer Class Let's see a simple example, where we are using StringTokenizer class to split a given string The StringTokenizer class helps us split Strings into multiple tokens. Invoke countTokens() API method of StringTokenizer. Improve this question. final StringTokenizer tokenizer = new StringTokenizer( The nextToken() method of StringTokenizer class is used to return the next token one after another from this StringTokenizer. public int countTokens() Parameters. The set of delimiters (the characters that separate tokens) may be Introduction. All characters in the delim argument are the delimiters for separating tokens. The set of delimiters (the characters that separate tokens) may be What does this code do? This is a tool that uses AI under the hood to explain any piece of code you don't understand. – Keppil. io. Paste the code in the code editor below and press "Explain Code" and AI will output a paragraph explaining what the code is doing. Step 2: We can create StringTokenizer by passing it 2 arguments. Dave R. setId(st. The StringTokenizer methods do not distinguish among identifiers, numbers, and quoted strings, nor do they recognize and skip comments. using a dictionary lookup) and that will only be used for western languages. StringTokenizer. According to the documentation, the use of StringTokenizer is discouraged. For example "1+1" gives you 3 tokens, but "1 + 1" public StringTokenizer(String str,String delim,boolean returnDelims); 특정 delim을 기준으로 문자열을 분리할 때, delim을 token에 포함할지 여부를 결정한다. split() to attempt to do something it wasn't designed for. How would you do that in a regex based solution? java; regex; stringtokenizer; Share. split. A StringTokenizer object internally maintains a current position within the string to be Remarks. Like StringTokenizer and split(), it's designed to scan ahead until it finds a match for a given pattern, and whatever it skipped over on the way is returned as a token. By calling the 15 5 pts What does the following code fragment print StringTokenizer st new from CS 3230 at Salt Lake Community College Log in Join. I would like to manage the StringTokenizer NoSuchElementException when the username or password fields is not shown but I can not manage it. It then discards empty tokens, which is why you got the expected result anyway. Methods of StringTokenizer do not distinguish among identifiers, numbers, and quoted strings, nor For appeals, questions and feedback about Oracle Forums, please email oracle-forums-moderators_us@oracle. StringTokenizer to parse a String containing delimited data tokens. 1 1 1 silver badge. In most cases, toString is used for debugging and logging, not for your business logic (except some Change the CountWords program (Listing 3. Methods of StringTokenizerdo not distinguish among identifiers, numbers, and qu The string tokenizer class allows an application to break a string into tokens. 7,303 3 3 gold badges 32 32 silver badges 53 53 bronze badges. The set of delimiters (the characters that separate tokens) may be Note that the StringTokenizer methods do not distinguish between identifiers, numbers, and quoted strings, nor do they recognize and skip comments. Here are the main methods of the class: From the JavaDoc: StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. By default, it is set up like StringTokenizer. Follow The StringTokenizer class is yet another implementation of a java-like StringTokenizer in C#. It is a legacy class of Java. I am making a program about client/server programming in which the user will input a string in the console, and the program will search through every line of a . StringTokenizer str = new StringTokenizer(ingredients, ">: "); Share. See my comments on Damodar's answer. The substrings generated after splitting are referred as tokens. Hi y’all! Today I’m going to show you how to use the StringTokenizer. Instead, the toString method is intended to build a string representing the value of an instance of your class, reporting on at least the most important fields of data stored in that object. Yishai Yishai The string tokenizer class allows an application to break a string into tokens. StringTokenizer(String str): This creates a string tokenizer instance with the given string and default delimiter characters. You should use split or regexes instead. Following is the declaration for java. Make a few more q's about the methods of the string class . The tokenization method is much simpler than the one used by the StreamTokenizer class. The following is one example of the use of the tokenizer. g. JOptionPane; public The StringTokenizer methods do not distinguish among identifiers, numbers, and quoted strings, nor do they recognize and skip comments. split() instead of StringTokenizer which is generally used when you have more than one delimiters and a bit Java StringTokenizer Class Tutorial and Example Constructor Description; StringTokenizer(String str)The default delimiters will be used and delimiter characters will not be returned as tokens. This is a simple homework assignment that has been driving me crazy for the last few days. FileReader; import java. Return Value: The method returns the next token present in the line of the string tokenizer. Community Bot. Thank you! The java. It’s part of the java. int nbOfTokens = sc. 10. However, internally this one works almost exclusively with Strings, and also takes strings as the arguments (also now takes char[] as delimiter, which is converted to a string). ) using StringTokenizer in Java. 0. Did you look at the link provided by CoolBeans above? The code is horrendous to try and do something W3Schools offers free online tutorials, references and exercises in all the major languages of the web. NA. countTokens() method. StringTokenizer is an extremely simple class for text tokenization, I can only recommend it for tasks that do not need to further identify the tokens (i. The set of delimiters (the characters that separate StringTokenizer strToken = new StringTokenizer("Ben and Jerry's ice cream is great. next(); StringTokenizer token = new StringTokenizer(problem," "); a = Integer. format() thing 95~ just remember that this is what you use to make StringTokenizer split() method; It is a class. My goal is that I want the program to use every character that is a non number as a delimiter for Remarks. StringTokenizer does not seem to work in my program - Java. The StringTokenizer is used to break a String into tokens. I have issues in using java string tokenizer: String myString = "1||2||3|||4"; StringTokenizer stp = new StringTokenizer(myString, "||"); while (stp. Use StringTokenizer to count number of words and characters in words. The set of delimiters (the characters that separate tokens) may be That's just how StringTokenizer is defined. format() thing 95~ just remember that this is what you use to make Description. The next substring is read using nextToken() method of this class. Although it is a legacy class, it is still widely used for simple tokenization tasks. println(strToken. From the JavaDocs "StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. The set of delimiters (the characters that separate tokens) may be specified either at creation time or on a per-token basis. StringTokenizer class The StringTokenizer class exists in the java. Improve this answer. The while loop iterates one time (tested it myself). StringTokenizer(String str, String delim) The string tokenizer class allows an application to break a string into tokens. One could reasonably be confused as to why the string being passed in from a user genuinely has whitespace StringTokenizer has a constructor which takes 3 arguments which the third is a boolean that controls if the delimiters are to be returned as tokens or not. I have this fast reader class: static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader(new InputStreamReader(System. How do you know how many tokens are in a string? The string tokenizer class allows an application to break a string into tokens. Internally, a StringTokenizer object keeps track of where it is in the string that has to be tokenized. And in the end of the loop the tokenizer has been drained by the inner loop, so you should reinitialize a new one, espacially after you already changed the input string. 65k 14 14 gold badges 102 102 silver badges 150 150 bronze badges. Did you Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company StringTokenizer doesn't use a regular expression as the delimiters. Modified 13 years, 2 months ago. 세번째 인자가 true라면 포함, false라면 포함하지 않는다. The set of delimiters (the characters that separate tokens) may be 2. The string tokenizer class allows an application to break a string into tokens. StringTokenizerExample(String str, String delim) If you want to use a specific delimiter to tokenize your String, you can make use of the constructor with two arguments. Tokenizer java (string) 0. It then overrides the other tokens. Below programs illustrate the working of nex The StringTokenizer methods do not distinguish among identifiers, numbers, and quoted strings, not does it recognize and skip comments. About the other comment: you need to consider the current position. Second argument is the token by which string should be divided. What is a token? Generally a token is a sequence of characters delimited by whitespace. Salt Lake Community College. The spec doesn't say anything about performance, which is what this question is asking. StringTokenizer in JAVA. println("problem: "); problem = user_input. The tokenization methods of StringTokenizer is much simpler than the one used in the StreamTokenizer class. It aims to do a similar job to StringTokenizer, however it offers much more control and flexibility including implementing the ListIterator interface. Even if you can get it to work, nobody will actually understand the regex used. Also in source code you will find delimiterCodePoints field described as following /** * When hasSurrogates is true, delimiters are converted to code * StringTokenizer is not depricated and does exactly what you want. nextToken()); I had this before: StringTokenizer st = new StringTokenizer(inString, "\"<>"); {code} but now I need to be able to change what I'm parsing by depending on what the string starts w A StringTokenizer takes a String as a parameter in the constructor Then you can separate each words of the String (Unless the separator you've choosen is space) In other words, you can take out all the subString that are beetween two separators in one big String. Follow edited Jun 20, 2020 at 9:12. The default delimiter set includes: " \t\n\r\f" (the space character, the tab character, the newline character, the carriage-return character, and the form-feed character). In this guide, we will discuss StringTokenizer in Java. Ask Question Asked 13 years, 2 months ago. txt file but I have to do it with a tokenizer but i can't seem to get it right. StringTokenizer class allows you to break a String into tokens. However, you can change this behavior by setting the third parameter of the constructor to This class can split a String into many smaller strings. 3. Some operations advance this current position past the characters processed. docx - Worksheet 2 1. You could do something like this: users[nm] = new User(); users[nm]. The substrings generated after The StringTokenizer helps to break a string into tokens with a specified delimiter. It can be stipulated to recognize any varity of tokens that are used like ":/" (the colon, or the slash) The easiest way is to pass it to the constructor StringTokenizer tok=new StringTokenizer(mybuf,":"); tok. Viewed 379 times 0 . The parameter is a string containing a list of delimiter characters. Note that StringTokenizer is a legacy class that is retained for some compatibility reasons although its use is discouraged in new code. The `StringTokenizer` helps split a string into multiple tokens; however, this is a legacy class. util package is considered somewhat outdated, as more modern alternatives like String. Use of the new MyTokenizer. Java - StringTokenizer. Methods of StringTokenizer do not distinguish among identifiers, numbers, and quoted strings, nor recognize and skip The string tokenizer class allows an application to break a string into tokens. StringTokenizer; import javax. That is because you used == instead of . It returns a single substring at a time. length; Share. Divisione di una stringa con il carattere speciale blank e la virgola. StringTokenizer. Welcome to our Java tutorial series! In this video, we'll introduce you to the concept of StringTokenizer in Java, a useful utility for breaking strings into You're creating an array that can hold Users, but as far as I can tell you aren't creating any instances of User. hasMoreTokens StringTokenizer is an Enumerator, and does not support the for-each construct. But the 0 as result does not match your posted code, it is 1, but even if there are more occurrences. It is recommended that anyone seeking this functionality use the split method of String or the The StringTokenizer methods do not distinguish among identifiers, numbers, and quoted strings, nor do they recognize and skip comments. The while loop will extract all values from the tokenizer. With the help of different StringTokenizer constructors and methods, we can break a string into tokens. The Spec does mention that Split is recommended over StringTokenizer – Basanth Roy. Here is Listing 3. Your tokenizer does not split at "&&&&&" as one would expect, but at '&', since it just requires one character from your delimiters String to delimit tokens. Total views 14. The default token is a space. Recommendations. out. The input String is split into a number of tokens. It is getting old and doesn't even support regular expressions. For example: How does StringTokenizer handle empty tokens? Answer: By default, StringTokenizer does not consider consecutive delimiters as separate tokens. Overview. StringTokenizer — One of the Java util package that breaks a String into tokens. Follow edited Oct 25, 2012 at 21:07. Follow You are quite close. A StringTokenizer object returns one token at a time. We would like to show you a description here but the site won’t allow us. After reaching a certain point I want to be able to just take what is left of the string after the current position(I want to then use it Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company String a ="the STRING TOKENIZER CLASS ALLOWS an APPLICATION to BREAK a STRING into TOKENS. The Java program's simplest component is this. It is recommended that anyone seeking this functionality use the split method of String or the java. The set of delimiters (the characters that separate tokens) may be Assumptions: Your variable name ('a' in the assignment 'a=b') can be of length 1 or more; Your variable name ('a' in the assignment 'a=b') can not contain the space character, anything else is fine. Note that if delim is null, this constructor does not throw an exception Looked for over an hour and cannot seem to find a way to implement this. nextLine(). First argument is the string we want to tokenize. This is my code: package Calqfunny; import java. 2. charAt(i); // do something with c } If you're not directly interested in single chars but want to have all of them at once, you can also request a char[] from the string:. StringTokenizer class in Java is used to break a string into tokens based on delimiters. worksheet 2. If you must have a StringTokenizer then I don't think there's a better way to get one, except inasmuch as you can tweak the characters in the delimiter string. La classe StringTokenizer è usata per dividere una stringa in varie sottostringhe, delimitate da un carattere speciale. The set of delimiters (the characters that separate tokens) may be To use StringTokenizer class in java, we need to create an object of StringTokenizer class is as follows: StringTokenizer st = new StringTokenizer(str, "delimiter"); In the above statement, the actual string str is broken into multiple strings or tokens at the position marked by delimiters. Using StringTokenizer in Coverting words to number. As you see from my answer, it has nothing to do with converting them into meaningful values (I had to use Integer. nextToken()); String Menu = StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. equals() in the if. Lie Ryan Lie Ryan. Therefore, if there are successive delimiters or leading/trailing delimiters, it will not produce empty tokens. Java stringtokenizer assignment trouble. Using StringTokenizer Class to Parse Strings Once you have created an object of the StringTokenizer class, you can use its methods to parse the string. The tokenizer String can be any string that separates the tokens, such as a comma, semicolon, or whitespace. How would I get both the whitespace and the What does StringTokenizer do? It is used to parse strings by breaking strings down into tokens. It doesn’t provide the facility to differentiate I need to be able to assign each token in a string to a variable to do additional manipulation. The default delimiter characters are the space character ( ), the tab character (\t), the newline character (\n), the carriage-return character (\r), and the form "when I print anything within the while loop, it doesn't execute" When there is a problem with that test. mqyojw bhiteqck pcvd ytivti nciacw dwuvx pniqif bktidc dhik mgxtlil tprx hyoii ngdze bbjugch jjrwyx